Question

. If AB is a diameter of the circle with centre O and angle ADC = 125°,
then angle BAC is
(a) 55°
(b) 35°
(c) 65 (2) 70​

Answer 1

Answer:

b) 34

Step-by-step explanation:

I I hope it will help you

Answer 2

Answer:

b) 35°

Step-by-step explanation:

HEY MATE HERE'S YOUR ANSWER!

Given, In circle with centre O, as AOB is diameter,

==> angle BCA= 90° [ Angle in a semicircle]

Now, In cyclic quadrilateral ABCD,

Angle ADC + angle ABC = 180° [ Opposite angles of a cyclic quadrilateral are supplementary]

==> 125° + angle ABC = 180°

==> angle ABC = 180° - 125°

==> angle ABC = 55°

Thus in ∆ABC, using Angle Sum Property of ∆,

angle ABC + angle BCA + angle BAC = 180°

==> 55° + 90° + angle BAC = 180°

==> 145° + angle BAC = 180°

==> angle BAC = 180° - 145°

==> angle BAC = 35°

THUS THE VALUE OF ANGLE BAC IS 35°.

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