if AB is a tangent drawn from a point A to a circle with centre O and BOC is a diameter of the circle such that angleAOC=120° then find angle OAB.
diagram for these and ans
Answers
Answered by
50
If helped plz mark as brainliest.
thank you, hope it helped
thank you, hope it helped
Attachments:
Answered by
78
☺☺ HERE IS YOUR ANSWER ☺......
========================================
In ∆ BOA,
Angle OBA = 90 . ..........(OB perpendicular tangent PB)
angle BOA + angle COA = 180. ........( linear angles)
angle BOA = 180 - 120
angle BOA = 60
Angle BOA + Angle ABO + Angle BAO = 180
60 + 90 + Angle BAO = 180
Angle BAO = 180 - 150
Angle BAO = 30.
========================================
HOPE IT HELPS.....
......... THANKS.........
========================================
In ∆ BOA,
Angle OBA = 90 . ..........(OB perpendicular tangent PB)
angle BOA + angle COA = 180. ........( linear angles)
angle BOA = 180 - 120
angle BOA = 60
Angle BOA + Angle ABO + Angle BAO = 180
60 + 90 + Angle BAO = 180
Angle BAO = 180 - 150
Angle BAO = 30.
========================================
HOPE IT HELPS.....
......... THANKS.........
Attachments:
Ãmanchavan:
thanks
Similar questions