Question

If √ab is an irrational number, prove that √a + √b is irrational, where a and b are non- negative integers.

Answer 1

Answer:

• gyan prakash verma

Step-by-step explanation:

let a = 2 , b = 3.

then, $\sqrt{a \: + \sqrt{b} }$= $\sqrt{2 + \sqrt{3} }$it is irrational no.and its $\sqrt{2 \times \sqrt{3 = \sqrt{6} } }$which is also irrational no. (proved)