Question

if AB is equal to 12 cm BC is equal to 16 cm and AB perpendicular to BC ,then what is the radius of the circle passing through the points A ,B and C?

Answer 1

By Pythagoras theorem, we know that

AC^2 = AB^2 + BC^2

          = (12)^2 + (16)^2

          = 144 + 256

          = 400.

AC = 20

Diameter of the circle = 20cm.

Radius will be r = d/2

                           = 10cm.


Hope this helps!

Answer 2

if AB=12cm,BC=16cm and AB is perpendicular to BC,then find the radius of the circle passing through the points A,B and C