Question

if ab is equal to AC and BC and CF are respectively the bisector of B and C so prove that triangle EBC congruent triangle FCB

Answer 1

In ∆ CBE & ∆ BCF ,

Ang(ABC) = Ang(ACB) .....(1) { Since, AB = AC }

1/2 Ang(ABC) = 1/2 Ang(ACB)

Ang(BCF) = Ang(CBE). ...... (2)

BC = CB { Common Side } .....(3)

From eqns (1) , (2) & (3) By (AngleSideAngle) Congruency Criterion.

∆ CBE congruent to ∆ BCF...