if ab is in intervertebral matrix of the same order then prove that a b whole inverse is equals to B inverse into a inverse
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Let " denote inverse
To prove : (AB)" = B"A"
Proof : AB(AB)" = I
A"AB(AB)" = A"I
IB(AB)" = A"
B(AB)" = A"
B"B(AB)" = B"A"
I(AB)" = B"A"
(AB)" = B"A"
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