if ab is ll to cd find the value of x y and z
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In triangle ABD
A+B+D= 180°
50°+70°+y=180°
y=180°-120°=60°
x+z=70°+50°(using exterior angle property)
x+z= 120°
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Answer:
In triangle ABD
A+B+D= 180°
50°+70°+y=180°
y=180°-120°=60°
x+z=70°+50°(using exterior angle property)
x+z= 120°
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