if AB is parallel to CD , angle APQ= 50 degree and angle PRD= 127 degree , find x and y.
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Answer:
plzz mention the type of figure..
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Answer:
x = 50° and y = 77°
Step-by-step explanation:
∠PQR=∠APQ (Alternate angle)
x=50°
∠PRQ+∠PRD=180°
∠PRQ+127° =180°
∠PRQ=180° − 127° =53°
∠PQR+∠QPR+∠PRQ=180°
(Angle sum property of triangle)
x+y+53° =180
50°+y+53° = 180°
y=180° − 103°
=77 °
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