If AB is parallel to CD find x
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In given figure AB ll CD
Draw a line segment BD it divides |_BDC is 90°
Angle BDE =140°-90°=50°
Angle DBE =150°-90°=60°
we know that sum of three angles in a triangle is 180°
angle BDE+ angleDBE+ angleBED=180°
50°+60°+angleBED =180°
110°+angleBED =180°
angleBED =180°-110°
angleBED =70°
Draw a line segment BD it divides |_BDC is 90°
Angle BDE =140°-90°=50°
Angle DBE =150°-90°=60°
we know that sum of three angles in a triangle is 180°
angle BDE+ angleDBE+ angleBED=180°
50°+60°+angleBED =180°
110°+angleBED =180°
angleBED =180°-110°
angleBED =70°
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I think is theproblem if may ne wrong please forgive me
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