Question

if ab is parallel to pq, if pq=1.5cm and qc=2cm and bq=8cm,the measure of ab is​

Answer 1

Answer:

Given : AB∥PQ, PQ=1.5cm,QC=2cm and BQ=8cm

Now, △PQC is 90°

∴ by Pythagoras theorem,

find the remaining in the attachment

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Answer 2

Answer:

7.5 cm

Step-by-step explanation:

In ∆ ABC and ∆ QPC

Angle C = Angle C (common)

Angle B= Angle Q ( each 90)

therefore ∆ABC ~ ∆ QPC (by AA)

therefore AB/QP = AC /QC

( corresponding sides of similar triangles are proportional )

AB /1.5 = 10/ 2

AB /1.5 =5

AB = 5×1.5

AB = 7.5 cm

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