Question

If AB is the diameter of a circle with centre O. AE = 12,
BE = 3 then CD=
a.10
b.12
c.15
d. 9
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Answer 1

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Answer 2

AE=12

BE=3

AND AB IS DIAMETER

THEREFORE THE GIVEN TWO SIDE MAKE AN ANGLE OF SEMI CIRCLE WHICH IS 90 DEGREE

NOW IN TRIANGLE AEB

ANGLE E IS 90 DEGREE

THEREFORE BY PYTHAGORAS THEOREM

H^2=B^2+P^2

AB^2=12^2+3^2

AB=√144+9

AB=√153

FOR THE REST ANSWER SEND THE DIAGRAM