If ab is the diameter of the circlre,the chord cd is perpendicular to ab intersecting at p.if cp=2cm and pb =1,what is the radius of the circle?
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Given : AB is the diameter of the circle, the chord CD is perpendicular to AB intersecting at P.
CP=2cm and PB =1 cm
To Find : radius of the circle
Solution:
AB is the diameter of the circle
=> AB = 2R
R is radius
PB = 1 cm
=> PA = 2R - 1 cm
Chord CD is perpendicular to Diameter (AB)
Hence CP = DP = 2 cm
PA * PB = CP * DP
=> 1 (2R - 1) = 2 * 2
=> 2R - 1 = 4
=> 2R = 5
=> R = 5/2
=> R = 2.5 cm
radius of the circle is 2.5 cm
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