Question

If AB ll CD and l is a transversal.

Find a+b

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Answer 1

Answer:

angle PRQ=PSQ=180°-55°

=125°

Therefore, 125°+ 125° =250°

a+b= 360°-250°= 110°(ans)

Answer 2

Answer:

= a + b = 110°

Step-by-step explanation:

AB is a straight line ;

Therefore,

Angle ARP + Angle PRQ + Angle BRQ = 180°

= 30° + Angle PRQ + 25° = 180°

= Angle PRQ = 180° - (30+25) = 180 - 55

= Angle PRQ = 125°

Similarly CD is also a straight line;

Therefore,

Angle CSP + Angle PSQ + Angle DSQ = 180°

= 20° + Angle PSQ + 35° = 180°

= Angle PSQ = 180° - (20+35) = 180 - 55

= Angle PSQ = 125°

Now in quadrilateral PSQR ;

Therefore,

Angle P + Angel S + Angle Q + Angle R = 360°

= a + 125° + b + 125° = 360°

= a + b = 360° - (125+125) = 360 - 250

= a + b = 110°