If AB n CD = pie and ADn BC = pie then ABCD is
Answers
Answered by
0
pcosθ+qsinθ
(p
2
+q
2
)sinθ
In the triangle BCD
cosα=
p
2
+q
2
q
and sinα=
p
2
+q
2
p
Using sine rule in triangle ABD
sinθ
AB
=
sin(θ+α)
BD
⇒AB=
sinθcosα+cosθsinα
p
2
+q
2
sinθ
=
p
2
+q
2
sinθ⋅q
+
p
2
+q
2
cosθ⋅p
p
2
+q
2
sinθ
⇒AB=
(pcosθ+qsinθ)
(p
2
+q
2
)sinθ
Similar questions