If AB parallel CD parallel EF, PQ parallel RS, angle RQD=25°and angle CQP=60°,then angle QRS is equal to
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Answer:
Step-by-step explanation:
AB//CD//EF
PQ//RS
RQD=25°
CQP=60°
NOW, WE HAVE PQ//RS
WE KNOW IF A TRANSVERSAL INTERSECTS TWO //LINES , THEN EACH PAIR OF ALTERNATE EXTERIOR ANGLES IS EQUAL.
SINCE ,PQ//RS
PQC=BRS
WE HAVE PQC= 60°
BRS=60°
WE KNOW , IF A TRANSVERSAL INTERSECTS TWO //LINES ,THEN EACH PAIR OF ALTERNATE INTERIOR ANGLES IS EQUAL.
SINCE ,AB// CD
DQR
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