if ab parallel de angle BAC is equal to 35 degree and angle CDE is equal to 50 degree find angle DCE
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∠DCE=∠EAB (Alternate angles as AB∣∣DE and AE is transversal)
∠DEC=35
∘
In △DCE, we have
∠DCE+∠CED+∠CED=180
∘
(Angle sum property)
∠DCE+35
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+53
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=180
∘
∠DCE=180
∘
−88
∘
=92
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