Question

. If (AB) vector =5i+3j-2k Find magnitude of (AB) vector. *

(a) √38

(b) 38

(c) 25

(d) 4​

Answer 1

Step-by-step explanation:

We have,

$\vec {AB} = 5 \hat{i} + 3 \hat{j} - 2 \hat{k}$

$|\vec {AB}| = \sqrt{5^{2} + 3 ^{2} + 2 ^{2} }$

$\implies |\vec {AB}| = \sqrt{25 + 9 + 4 }$

$\implies |\vec {AB}| = \sqrt{38 }$

Answer 2

Answer:

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