Question

If AB=x+3, BC = 2x, AC = 4x-5, then what will be the measure
of'x, if 'B' lies on AC. Justify your answer.​

Answer 1

Answer:

$\large\bold\red{x=8}$

Step-by-step explanation:

Given,

• AB = x + 3
• BC = 2x
• AC = 4x - 5

Also,

• B lies on AC

Therefore,

We have,

• AB + BC = AC

Thus,

We get,

$= >( x + 3) + (2x) = (4x - 5) \\ \\ = > x + 2x + 3 = 4x - 5 \\ \\ = > 3x + 3 = 4x - 5 \\ \\ = > 4x - 3x = 3 + 5 \\ \\ = > \bold{x = 8}$

Hence,

x = 8

Answer 2

Solution :

Given ,

AB = x + 3 , BC = 2x , AC = 4x - 5

and B lies on AC

So ,

AB + BC = AC ------- (i)

Substitute the values in eq (i) , we get

$\sf \hookrightarrow(x + 3) + (2x) = (4x - 5) \\ \\ \sf \hookrightarrow 3x + 3 = 4x - 5 \\ \\\sf \hookrightarrow x = 8$

Therefore , the required value of x is 8 respectively