If AB4234C is divisible by 3, then the maximum value of A+ B + C is
(a) 24 (b)25 (c) 26 (d) 27
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Step-by-step explanation:
d) 27 broooooo
it is the maximum
Answered by
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Answer:
Sum of digits = 4+2+3+4+A+B+C=13+A+B+C
For divisibility by 3,
The sum of the digits should be divisible by 3
So A+B+C should be 26 for the number to be divisible by 3
hulkgamma:
nice one bro
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