Question

If ABB×999=ABC123(wherA,B,C are digits)find the value of A,B,C

Answer 1

Given,

ABB×999=ABC123

To find,

value of A,B and C

Let A be 8,

B be 7  

C be 6.

Calculation,

When we multiply  

=>877×999=876123.

Hope its help

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Answer 2

Answer:

A = 8 , B = 7 , C = 6

Step-by-step explanation:

We are given with a statement, ABB × 999 = ABC123

To find: Value of A , B , C

First B is in ones place of ABB which is multiplied with 9 of 999 and product of B & 9 gives 3 in ones place.

this only possible if B = 7 as 7 × 9 = 63

So Now we have,  A77 × 999 = A7C123

Now Solving this we get A = 8 and C = 6

Therefore, A = 8 , B = 7 , C = 6