Question

if abc=2, then the value of 1/1+a+2b¹ + 1/1+1/2+2b¹+1/1+c+a¹ is​

Answer 1

Answer:

Given, 1/a + 1/b + 1/c = 1 . Multiplying both sides by abc

bc + ca + ab = abc……………………………………………………………………………….(1)

We have to find the value of

ab²c² + a²bc ² + a²b²c = abc (bc+ca+ab) Using eq.(1) to replace bc+ca+ab by abc

= abc . abc

But we are given that abc = 2. Substituting for abc =2,

Value of the expression

ab²c² + a²bc ² + a²b²c =2.2 = 4 (Proved)