If ΔABC and ΔBDE are equilateral triangles, where D is the mid point of BC, find the ratio of areas of ΔABC and ΔBDE.
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In a ΔABC , perpendicular AD from A on BC meets BC at D. If BD = 8 cm, DC = 2 cm and AD = 4 cm, then
A.ΔABC is isosceles
B. ΔABC is equilateral
C. AC = 2 AB
D. ΔABC is right-angled at A.
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Sorry my dear sister for wrong answer
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