Question

If ABC and DBC are the two isosceles triangle drawn on opposite sides of the same base BC and A,D are joined, prove that AD bisects each of the angles BAC and BDC.
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No
Sorry I am not Marathi
As I am from Uttarakhand
:l​

Answer 1

Explanation:

Step-by-step explanation:

construction:- draw AE and DE

perpendicular to BC now, in triangle triangle AEC and triangle

AEB

AE = AE (common)

CE = BE (as perpendicular bisects base in an isosceles triangle)

angle AEC = angle AEB (each 90)

therefore, triangle AEC is congruent to triangle AEB( by RHS congruency rule)

so, angle EAB = EAC (corresponding parts of congruent triangles)

similarly, triangle BDE = triangle CDE

therefore angle BDE = angle CDE

Answer 2

Answer:

hi domb how are you I am also from Uttarakhand

Explanation:

this is your ans

... two isosceles triangle drawn on the opposite side of the same base BC and AE joined prove that ad bisects each of the angle