if ABC and DBC are two isosceles triangle on the same base BC then
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Given ΔABC and ΔDBC are two isosceles triangles on the same base BC
In isosceles ΔABC
AB=AC
Then ∠ABC=∠ACB................................(1)
In isosceles ΔBDC
BD=DC
Then ∠CBD=∠BCD..................................(2)
Add (1) and (2) we get
∠ABC+∠CBD=∠ACB+∠BCD
But ΔABC and ΔDBC on same base
∴∠ABD=∠ACD
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