If ΔABC and ΔDEF are two triangles such that AB/DE = BC/EF =CA/FD =2/5, then Area (ΔABC): Area (ΔDEF) =
A. 2 : 5
B. 4 : 25
C. 4 : 15
D. 8 : 125
Answers
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4
Answer: B
ΔABC∽ΔDEF is true because of SSS.
And we are given the ratio of similarity. 2:5.
¹*Ratio of area is 2²:5²=4:25.
Answer is B.
¹*Because base and height of two triangles follows the ratio.
Let the ratio of similarity be a:b
Then area of first triangle is (1/2)*base*a*height*a
Second triangle is (1/2)*base*b*height*b
Hence proved. The ratio of area is a²:b².
Answered by
1
Answer:
In ΔABC, D and E are points on side AB and AC respectively such that DE||BC and AD: DB = 3 : 1. If EA = 3.3 cm, then AC =
A. 1.1 cm
B. 4 cm
C. 4.4 cm
D. 5.5 cm
Step-by-step explanation:
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