Math, asked by libra8397, 10 months ago

If ABC are distinct single digit natural numbers satisfying: A B C + A C B B C A Find the values of A,B,C.

Answers

Answered by ks2512
2

20)B<= 9 & A <=4

B+C>= C. This is only possible if B is 9 and there is a carry of one from unit place.

So B=9.

2A + 1 = B, So A =4.

C + B = A, So C+9 = 4 ⇒ C=5

Answered by sangeeta7paulsl
0

Answer:

A= 4, B=9 ,C=5

Step-by-step explanation:

B<= 9 & A <=4

B+C>= C.

This is only possible if B is 9 and there is a carry of one from unit place.

So B=9.

2A + 1 = B,

So A =4.

C + B = A,

So C+9 = 4 ⇒ C=5

#SPJ3

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