If ABC are distinct single digit natural numbers satisfying: A B C + A C B B C A Find the values of A,B,C.
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Answered by
2
20)B<= 9 & A <=4
B+C>= C. This is only possible if B is 9 and there is a carry of one from unit place.
So B=9.
2A + 1 = B, So A =4.
C + B = A, So C+9 = 4 ⇒ C=5
Answered by
0
Answer:
A= 4, B=9 ,C=5
Step-by-step explanation:
B<= 9 & A <=4
B+C>= C.
This is only possible if B is 9 and there is a carry of one from unit place.
So B=9.
2A + 1 = B,
So A =4.
C + B = A,
So C+9 = 4 ⇒ C=5
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