Question

If abc-cba=792,where abc is three digit number,a+b+c=18and a=9c,then the no is

Answer 1

Step-by-step explanation:

abc−bca=792

99(a−c)=792

a−c=8

Therefore,

c=1 and a=9

Now, using $$a+b+c=18, we get

9+b+1=18

b=8

Thus, the number = abc=981