Question

if ∆ABC~∆DEF;And ab=6cm bc=4.5cm ac=7.5 CM de=4cm ef=3cm then df=​

Answer 1

Answer:

Steps of Construction:

i) Draw a line segment BC = 4.5 cm

ii) With B as centre and radius 6 cm and C as centre and radius 5 cm, draw arcs which intersect each other at A.

iii) Join AB and AC.

ABC is the required triangle.

iv) Draw the angle bisector of ∠BAC

v) Draw lines parallel to AB and AC at a distance of 2 cm, which intersect each other and AD at O.

vi) With centre O and radius 2 cm, draw a circle which touches AB and AC.

Answer 2

Answer:

DF = 5 cm

refer to the attached image for explanation.......

Step-by-step explanation:

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