Question

If ∆ABC ~ ∆ DEF and angle A=30°; AngleB = 50° then Angle E + Angle F is equal to ____

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Answer 1

Answer:

150°

Step-by-step explanation:

Given,

∆ABC~∆DEF, then:

In∆ABC and ∆DEF,

Angle A = Angle D = 30°

Angle B = Angle E = 50°

Angle C = Angle F = {180°-(30°+50°)} =100°

(By angle sum property of ∆)

therefore,

Angle E + Angle F = 100°+50°=150°

Answer 2

Answer:

∠E + ∠F  = 150°

Step-by-step explanation:

The sum of three angles of a triangle = 180°

ΔABC = 180°

∠A = 30°

∠B = 50°

∠C = 180° - (50° + 30°)

∠C = 180° - 80°

∠C = 100°

ΔABC ~ΔDEF

∠A = ∠D = 30°

∠B = ∠E  = 50°

∠C = ∠F  = 100°

∠E + ∠F  = 100° + 50° = 150°