Question

If ∆ABC~∆DEF and EF=1
3
BC,then ar(∆ABC):( ∆DEF) is…

Answer 1

Given:

It is observed that during the motion of a body, its acceleration is zero.

To draw:

The Distance-Time and Velocity-Time graph for this situation.

Solution:

First of all, the acceleration of the body is zero, so we can say that the velocity of the body is constant. Hence, the velocity of the body does not increase with time.

So, when we will plot the velocity-time graph, the graph will be a linear line parallel to time axis.

Now, we know that relationship:

$\rm\therefore \: s = u \times t∴s=u×t$

$\rm\implies\: s \propto t \: (for \: constant \: velocity)⟹s∝t(forconstantvelocity)$

So, when we will plot the Distance time graph, the graph will be a linear line with a positive slope.

$\star$ Hope It Helps.

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