Question

If ∆ABC ~= ∆DEF, angle A = 100° and angle B = 45°then angle F = ?​

Answer 1

☺️☺️ HERE is your Answer ☺️☺️

{ANGLE\:F=35°

➡️ In ∆ abc In∆abc

=> a = 100°

=> b = 45°

As ∆ def As∆def

=> ANGLE A = ANGLE D ( congruent triangles)

=> Angle D = 100°

=> Angle B = Angle E ( congruent triangle)

=> Angle E = 45°

AS WE HAVE GOT TWO ANGLES WE CAN FIND THE THIRD ONE.

Angle F = 180 - (Angle A+ Angle B)..ANGLE SUM PROPERTY AngleF=180−(AngleA+AngleB).

=> ANGLE F = 180 - (100 + 45 )

=> ANGLE F = 180 - 145

=> ANGLE F = 35°

THEREFORE ANGLE F = 35°

Answer 2

717&281+(1) (191(91+82+3(393(394

Step-by-step explanation:

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