Math, asked by grnikam007, 2 months ago

If ΔABC~ΔDEF, area of ΔDCF=4/9(area of ΔABC) then BC/EF=?​

Answers

Answered by TNanushreebhardwaj
0

BC/EF = 3/2

We know ∆ABC~∆DEF

AREA of ∆DEF = 4/9 (area ∆ABC)(GIVEN)

area (∆DEF)/area (∆ ABC) =4/9

Now,

Ratio of two similar ∆'s is equal to square of ratio of corresponding sides

area (∆DEF)/area (∆ ABC) =4/9 = (EF/BC)²

= 2/3 = EF/BC

= BC/EF = 3/2

BC:EF = 3:2

For further reference for Area of triangle please refer to :

https://brainly.in/question/15014860

Similar questions