If △ ABC ~ △ DEF such that AB = 12 cm and DE = 14 cm. Find the ratio of areas of △ ABC and △ DEF.
49/9
36/49
49/16
25/49
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Answers
Answered by
25
We know that the ratio of areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides.
Therefore ,
Area of ( ∆ ABC ) / Area of ( ∆ DEF ) = AB^2 / DE^2
=> Area of ( ∆ ABC ) / Area of ( ∆ DEF )
=> ( 1.2 )^2 / ( 1.2 )^2
=> ( 12/14 )^2
=> 36/49
Hence 36/49 is your answer
Answered by
3
Answer:
36/49
Step-by-step explanation:
(12) squer / (14) squer =144/196=72/98=36/49
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