If ABC DEF ~ , then match the following : [ ]
List - I List - II
i) AB : DE = 2 : 3, then BC : EF = A) 1 : 2
ii) AC : DF = 2 : 3, then Ar ABC Ar DEF : B) 2 : 3
iii) Perimeter of ABC DEF : 1: 2 , then AC : DF = C) 4 : 9
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