if ∆ ABC ~ ∆ EDC , AC = 15 , BC = 10 , CE = 12 then find CD
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Answered by
11
Answer:
ac/ec=bc/dc
15/12=10/dc
15dc=120
dc=8
Answered by
12
We know that if ∆ABC ~ ∆EDC,
AC/ED = BC/DC = AC/EC.
THUS,
15 / ED = 10/CD =15/12
•°• 10/CD = 5/4
OR, CD = 4×10/5
OR , CD = 8.
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