Math, asked by deshmukhmahesh325, 7 months ago

if ∆ ABC ~ ∆ EDC , AC = 15 , BC = 10 , CE = 12 then find CD​

Answers

Answered by sowmya03bhaskar
11

Answer:

ac/ec=bc/dc

15/12=10/dc

15dc=120

dc=8

Answered by tapajyotirkmv
12

We know that if ∆ABC ~ ∆EDC,

AC/ED = BC/DC = AC/EC.

THUS,

15 / ED = 10/CD =15/12

•°• 10/CD = 5/4

OR, CD = 4×10/5

OR , CD = 8.

HOPE THIS HELPS U.......

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