Question

if ∆ABC ~∆EDF such that Ab=5cm ,ac 10 cm ,ed =12cm and DF 24cm then eg snd bc are respectively equal to​

Answer 1

Answer:

EF = 24, BC = 10

Step-by-step explanation:

Since, ∆ABC ~ ∆EDF

AB/ED = BC/DF

5/12 = BC/24

24x5/12 = BC

120/12 = BC

BC = 10cm

Now, AC/EF = BC/DF

10/EF = 10/24

10x24/10 = EF

240/10 = EF

EF = 24cm

Answer 2

Step-by-step explanation:

Given: ABC ~∆EDF such that AB=5cm , AC 10 cm , ED =12cm and DF= 24cm.

To find: EF and BC are respectively equal to?

Solution:

Tip: If two triangles are similar, then ratio of their corresponding sides are equal and corresponding angles are equal.

According to question,

$\frac{AB}{ED}=\frac{BC}{DF}=\frac{AC}{EF}$

put the given values

$\frac{5}{12}=\frac{BC}{24}=\frac{10}{EF}$

Solve first two

$\frac{5}{12}=\frac{BC}{24}$

or

$\frac{5\times 24}{12}={BC}$

BC=10 cm

Solve for EF, by taking first and last terms

$\frac{5}{12}=\frac{10}{EF}$

or

$\frac{12\times10}{5}=EF$

or

EF=24 cm

Final answer:

Values of BC and EF are 10 cm and 24 cm respectively.

Hope it helps you.

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