if ∆ABC ~= ∆FDE and AB=5cm, angle B=40° and angle A=80°, then find the value of DF and angle E
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Given:
- ∆ABC ≅ ∆FDE
- AB = 5 cm
- ∠B = 40°
- ∠A = 80°
To find:
- DF?
- ∠E?
Solution:
Given that,
∆ABC ≅ ∆FDE
then,
AB = FD
BC = DF
AC = FE
And,
∠ABC = ∠FDE
∠BCA = ∠DEF
∠CAB = ∠EFD
Here, Given that,
- AB = 5 cm
- B = 40°
- A = 80°
So,
∠FDE = 40° [ ∠ABC = ∠FDE ]
∠EFD = 80° [ ∠CAB = ∠EFD ]
FD = 5 cm [ AB = FD ]
We know that,
→ ∠D + ∠E + ∠F = 180° [ Angle sum property ]
→ 40° + ∠E + 80° = 180°
→ ∠E + 120° = 180°
→ ∠E = 180° - 120°
→ ∠E = 60°
∴ Hence, ∠DEF = 60° and DF = 5 cm.
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