If ABC is a quadrilateral in which AB ||CD and AD =BC, prove that <A=<B.
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see the attached figure ,
given ,
AB = CD
AD = BC
to prove that : ABCD is a IIgram
proof :- AB = CD (from the given )
BC = AD (from the given )
BD = BD (common side )
∴ Δ ADB ≡ Δ DBC by SSS congruence rule .
therefore from CPCT we can write that ∠ADB = ∠ DBC (alternate interior angle )
since the alternate interior angles and opposite sides are equal in a quadrilateral therefore it is a IIgram .
i hope it helps ...........................^_^
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shakku52:
kon
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hey mate, I am parth dhami
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