If ABC is a right angel isosceles triangle then find greatest angel
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Answer:
Since AB=AC,
So, △ABC is Right-angled isosceles.
∠B=∠C ...(angles opp. to equal sides are equal)
∠A+∠B+∠C=180
∘
...(angle - sum property of a triangle)
Substituting ∠B=∠C, ∠A=90
o
90
∘
+2∠B=180
∘
2∠B=180
∘
–90
∘
=90
∘
⇒∠B=45
∘
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