Question

if ABC is a right angle triangle and angle B is 90°,a object from point A to B is 4 k.m and from B to c is 3 k.m reachy at point c than what is its displacement at c​

Answer 1

Step-by-step explanation:

(i) let ∠CAD = x ⇒ m ∠dab = 90° - x ⇒ m ∠DBA = 180° - (90° + 90° - x) = x ⇒ ∠CDA = ∠DBA ……… (1) In ΔADB and ΔCDA, ∠ADB = ∠CDA …… [each 90°] ∠ABD = ∠CAD …… [From (1)] ∴ΔADB ~ ΔCDA …….. [By A.A] (ii) Since the corresponding sides of similar triangles are proportional, we have. (iii) The ratio of the areas of two similar triangles is equal to the ratio of the square of their corresponding sides.

Hope this will help you

Mark me as brilliant

Answer 2

$(ab) {}^{2} + (bc) {}^{2} = (ac) { }^{2} \\ {4}^{2} + {3}^{2} = (ac) {}^{2} \\ 16 + 9 = (ac) {}^{2} \\ 25 = (ac) {}^{2} \\ \sqrt{25} = ac \\ 5cm = ac$

displacement= 5cm