If ΔABC is a right triangle such that ∠C= 90°,∠A = 45° and BC = 7 units. Find ∠B, AB and AC.
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Answer:
∠B=45° AC=7 units. AB=7√2 units
Step-by-step explanation:
∠A+∠B+∠C=180°
45°+∠B+90°=180°
∠B=180°-135°
∠B=45°
tan∠A=BC/AC
tan45°=7/AC
1=7/AC
AC=7 units
In ∆ABC,
AB^2=AC^2+BC^2
AB^2=7^2+7^2
AB^2=49+49
AB=7√2 units
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