Question

if abc is a three digit number, prove that abc +bca +cab is a multiple of 111

Answer 1

if ABC is a three digit number it can be written as 100a+b+c
bca=100b+10c+a
cab=100c+10a+b

adding all these we get ABC+bca+cab= 111(a+b+c)

so it's always a multiple of 111

Answer 2

Answer:

ABC is a three digit number it can be written as 100a+b+c

bca=100b+10c+a

cab=100c+10a+b

adding all these we get ABC+bca+cab= 111(a+b+c)

so it's always a multiple of 111

Step-by-step explanation: