Question

If abc is a three digit number, write the number bca and cab in expanded from. Show that the sum of abc, bca andcab divisible by 111.

Answer 1

Answer:

abc+bca+cab=100a+10b+c+100b+10c+a+100c+10a+b=100(a+b+c)+10(a+b+c)+(a+b+c)=(a+b+c)(100+10+1)=(a+b+c)(111).it is divisible by 111.