Math, asked by shreyash619, 15 days ago

If ABC is a triangle and angle B=90 degree
Show that AB^2+BC^2=AC^2

Answers

Answered by samayetasamanta
1

Answer:

according to Pythagoras theorem , you can easily prove this.

Step-by-step explanation:

hope that it helps

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Answered by ganeshmandaljsr86
1

Answer:

q

Step-by-step explanation:

Given: In △ABC,m∠B=90

o

To prove: AC

2

=AB

2

+BC

2

Construction: Draw BD⊥AC

Proof: We know that: If a perpendicular is drawn from the vertex of the right angle of a right angled triangle to the hypotenuse, then triangles on both sides of the perpendicular are similar to the whole triangle and to each other.

△ADB∼△ABC

So,

AB

AD

=

AC

AB

(Sides are proportional)

or AD.AC=AB

2

....(1)

Also, △BDC∼△ABC

So,

BC

CD

=

AC

BC

CD.AC=BC

2

...(2)

Or CD.AC=BC

2

....(2)

Adding (1) and (2)

AD.AC+CD.AC=AB

2

+BC

2

AC(AD+CD)=AB

2

+BC

2

AC.AC=AB

2

+BC

2

AC

2

=AB

2

+BC

2

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