If ABC is a triangle and the relation between angles is A-B=15° and B-C=30°,then find the values of the angles
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Answer:
We have,
A−B=15
∘
......(1)
B−C=30
∘
B=C+30
∘
......(2)
On adding both equation, we get
A−C=45
∘
A=C+45
∘
......(3)
In a triangle,
A+B+C=180
∘
......(4)
Substituting the value from equation (1) and (2), we get
C+45
∘
+C+30
∘
+C=180
∘
3C=105
∘
∠C=35
∘
.
Substituting this value in equation (1) and (2), we get
∠B=65
∘
∠A=80
∘
Hence, the angles are ∠A=80
∘
∠B=65
∘
∠C=35
∘
.
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