If abc is a triangle right angled at c then cos(a+b) is equal to
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a+b+c=180(sum of all angles of a triangle is 180°)
a+b=180-c
cos(a+b)=cos(180-c)
cos(a+b)=cos(180-90)
cos(a+b)=cos 90
cos(a+b)=0
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