Question

If abc is a triangle with equal sides, a line Xy is drawn parallel to Bc, And ratio of Ax :xb is found to be 3:5 The lengths of Ay Yc are found to be 9,15 respectively. Find AX, XB, AND BC

Answer 1

Given ABC is a triangle with equal sides then

AB= BC =CA

→ Given XY// BC

Then, AB = AX+XB
AC = AY+YC

According to side splitter theorem,

AX/ XB = AY/YC

Given, AX / XB =3:5,AY = 9 cm, YC = 15 cm

3x/5x = 9/15

Here x = any natural number but as the triangle is Equilateral, AX = AY,XB= YC

Length of AB = Length of AC = Length of BC



So, BC =9+15= 24 cm, XB = 15 cm, AX= 9 cm

hope helped!

Answer 2

Heya !
_____________________________________________________________

Here !
_____________________________________________________________
ΔABC is equilateral 
ATQ 
AB = BC = AC 
AY + YC = AX + XB 
9 + 15     =  24 
we know AX/XB = 3/5 
so 3x + 5x = 24 
   8x           = 24 
      x = 3 
AX = 3 x 3 = 9 
XB = 3 X 5 = 15 
BC = AC = AB = 9 + 15 = 24 cm 
_____________________________________________________________