Question

If ABC is an isosceles triangle and 60° <A <90°,
then show that c <a√2c.
​

Answer 1

Answer:

Use the law of cosines to show that a=c*sqrt[2(1-cos A)] and the conclusion follows..

If you haven't had the law of cosines yet, please let me know and I will see if I can help further.

Step-by-step explanation:

Please give me a point and please make me brainless I hope I can help you good day