Question

If ABC is an isosceles triangle such that AB=AC,then prove that altitude AD from A on BC bisects it​

Answer 1

Answer:

There are two right triangles ADB and ADC we have

Hyp. AB = Hyp. AC (Given)

AD = AD (Comman side)

So by RHS criterion of congruence

△ADB≅△ADC

BD = DC ( ∵ Corresponding parts of congruent triangles are equal )

Answer 2

Answer:

here's what's ur ques ¿?

If ABC is an isosceles triangle such that AB=AC,then prove that altitude AD from A on BC bisects it?

In ∆ADB and ∆ADC AD = AD [Common side]

∠APB =∠ ADC [90°] BD = DC [AD bisects BC]

∴∆ADB ≅ ∆ADC [SAS postulate]

∴AB = AC [Corresponding sides]

∴∆ ABC is an isosceles triangle

Regarding =hope it helps have a great day