If abc is an isosceles triangle with ab=ac=5 and bc=6. if g is centroid of triangle abc then ag is equal to
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ab=ac=5 bc=6 angle equal to 11
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Let GD=x
so that AG=2x
∴AD=x+2x=3x
Since is a median, therefore
BD= ½×BC=½×6=3
From right angled ΔABCAB³ =BD²+AD²
or 5²=⅔+(3x)²
or 25+9+9x²
or 9x² =16
or x² = 16/9
or x= 4/3
HEnce, AG=2x
=2×4/3= 8/3
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